What is the first derivative of bx^2 ?

The first derivative of bx^2 is 2bx

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derivative of bx^2

\frac{d}{d x} (b x^{2})

2 b x

Solution steps

\frac{d}{d x} (b x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= b \cdot 2 x^{2 - 1}

Simplify

= 2 b x

\frac{d}{d x} ((2 x + 6)^{2})

y = (2 x - 2)^{4} (x^{2} + x + 1)^{5}

\int e^{x^{2} + l n (x)} d x

\frac{2}{x - 8}

\frac{d y}{d x} = \frac{5 x sec ( \frac{y}{x} ) + y}{x}