What is the derivative of xy+y-1 ?

The derivative of xy+y-1 is x(dy)/(dx)+y+(dy)/(dx)

What is the first derivative of xy+y-1 ?

The first derivative of xy+y-1 is x(dy)/(dx)+y+(dy)/(dx)

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\frac{d}{d x} (x y + y - 1)

x \frac{d y}{d x} + y + \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x y + y - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x y) + \frac{d y}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

\frac{d}{d x} (1) = 0

= y + x \frac{d y}{d x} + \frac{d y}{d x} - 0

Simplify

= x \frac{d y}{d x} + y + \frac{d y}{d x}

\int_{4}^{5} \frac{1}{( x - 4 ) ^{\frac{4}{3}}} d x

f (x) = e^{x + 2} + 1

\frac{d}{d x} (\frac{x ^{2} - 2}{x - 1})

x \to 0 lim (ln ∣ x ∣)

\frac{d}{d x} (\frac{x + 3}{2})

What is the derivative of xy+y-1 ?
The derivative of xy+y-1 is x(dy)/(dx)+y+(dy)/(dx)
What is the first derivative of xy+y-1 ?
The first derivative of xy+y-1 is x(dy)/(dx)+y+(dy)/(dx)