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Popular >

xy^'=(1-y^2)^{1/2}

Solution

x y^{^{'}} = (1 - y^{2})^{\frac{1}{2}}

Solution

y = sin (ln (x) + c_{1})

Solution steps

x y^{'} (x) = (1 - y^{2})^{\frac{1}{2}}

Solve separable ODE:

y = sin (ln (x) + c_{1})

y = sin (ln (x) + c_{1})

Graph

Popular Examples

derivative of y=(x+1)/(x^3+x-2)derivative of

y = \frac{x + 1}{x ^{3} + x - 2}

f(x)=sin(9ln(x))

f (x) = sin (9 ln (x))

limit as x approaches 8 of x^{(2/3)}

x \to 8 lim (x^{(\frac{2}{3})})

x^{^{''}} = k^{2} x

(\partial)/(\partial x)(x*sin(x^2-y^2))

\frac{\partial}{\partial x} (x \cdot sin (x^{2} - y^{2}))

Frequently Asked Questions (FAQ)

What is the solution for xy^'=(1-y^2)^{1/2} ?
The solution for xy^'=(1-y^2)^{1/2} is y=sin(ln(x)+c_{1})