What is (\partial)/(\partial z)(x^2+z^2) ?

The answer to (\partial)/(\partial z)(x^2+z^2) is 2z

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(\partial)/(\partial z)(x^2+z^2)

\frac{\partial}{\partial z} (x^{2} + z^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (x^{2} + z^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x^{2}) + \frac{\partial}{\partial z} (z^{2})

\frac{\partial}{\partial z} (x^{2}) = 0

\frac{\partial}{\partial z} (z^{2}) = 2 z

= 0 + 2 z

Simplify

= 2 z

y^{^{''}} + y = 3 sin (2 t) + t cos (2 t)

x \to - 1 lim (1 - x^{2})

\int \frac{2}{3} x^{\frac{3}{2}} - 4 sin (x) + C d x

\frac{d}{d x} ((2 x - 1)^{3})

\frac{1}{cos ( t )}

What is (\partial)/(\partial z)(x^2+z^2) ?
The answer to (\partial)/(\partial z)(x^2+z^2) is 2z