What is the derivative of 3x-2y ?

The derivative of 3x-2y is 3-2(dy)/(dx)

What is the first derivative of 3x-2y ?

The first derivative of 3x-2y is 3-2(dy)/(dx)

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\frac{d}{d x} (3 x - 2 y)

3 - 2 \frac{d y}{d x}

Solution steps

\frac{d}{d x} (3 x - 2 y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) - \frac{d}{d x} (2 y)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2 y) = 2 \frac{d y}{d x}

= 3 - 2 \frac{d y}{d x}

\int_{1}^{e} \frac{ln ( 2 x )}{x} d x

\frac{d}{d t} (cos^{3} (3 t^{2}))

\frac{v}{v - 1}

x \to 0 lim (\frac{sin ( x )}{5 x})

\int (x^{3} + 1)^{2} \cdot x^{2} d x

What is the derivative of 3x-2y ?
The derivative of 3x-2y is 3-2(dy)/(dx)
What is the first derivative of 3x-2y ?
The first derivative of 3x-2y is 3-2(dy)/(dx)