What is the solution for y^{''}-y^'-30y=0,y(0)=3,y^'(0)=-3 ?

The solution for y^{''}-y^'-30y=0,y(0)=3,y^'(0)=-3 is y=(3-21/11)e^{6t}+21/11 e^{-5t}

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y^{''}-y^'-30y=0,y(0)=3,y^'(0)=-3

y^{^{''}} - y^{^{'}} - 30 y = 0, y (0) = 3, y^{^{'}} (0) = - 3

y = (3 - \frac{21}{11}) e^{6 t} + \frac{21}{11} e^{- 5 t}

Solution steps

y^{''} (t) - y^{'} (t) - 30 y = 0

Solve linear ODE:

y = (3 - \frac{21}{11}) e^{6 t} + \frac{21}{11} e^{- 5 t}

y = (3 - \frac{21}{11}) e^{6 t} + \frac{21}{11} e^{- 5 t}

\frac{\partial}{\partial θ} (r (θ) sin (θ))

y = x - x^{3}

y \to 0 lim (\frac{y}{sin ( 5 y )})

x \to 2 lim (x - 4)

e^{x - 2}

What is the solution for y^{''}-y^'-30y=0,y(0)=3,y^'(0)=-3 ?
The solution for y^{''}-y^'-30y=0,y(0)=3,y^'(0)=-3 is y=(3-21/11)e^{6t}+21/11 e^{-5t}