What is the derivative of f(x)=x^4+9x ?

The derivative of f(x)=x^4+9x is 4x^3+9

What is the first derivative of f(x)=x^4+9x ?

The first derivative of f(x)=x^4+9x is 4x^3+9

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derivative of

f (x) = x^{4} + 9 x

4 x^{3} + 9

Solution steps

\frac{d}{d x} (x^{4} + 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (9 x) = 9

= 4 x^{3} + 9

\int cos (x) sin (y) d x

x \to \infty lim (4, x)

\frac{\partial}{\partial x} (sec^{2} (2 x + 3 y) \cdot 3)

\frac{\partial}{\partial x} (x - 2 y + 2 z)

\frac{d}{d x} ((\frac{x ^{3} - 1}{x ^{3} + 1})^{8})

What is the derivative of f(x)=x^4+9x ?
The derivative of f(x)=x^4+9x is 4x^3+9
What is the first derivative of f(x)=x^4+9x ?
The first derivative of f(x)=x^4+9x is 4x^3+9