What is the sum from n=0 to infinity of (n/(n+2))^n ?

The sum from n=0 to infinity of (n/(n+2))^n is diverges

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sum from n=0 to infinity of (n/(n+2))^n

n = 0 \sum \infty (\frac{n}{n + 2})^{n}

diverges

Solution steps

n = 1 \sum \infty (\frac{n}{n + 2})^{n}

Apply Series Divergence Test:

diverges

= diverges

11 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 8

x \to 2 lim (\frac{5}{x})

\int_{0}^{\infty} 4 e^{- x} d x

\int (\frac{x}{2 x + 1}) d x

\frac{d}{d x} (- 5^{8 x^{2} - 1})

What is the sum from n=0 to infinity of (n/(n+2))^n ?
The sum from n=0 to infinity of (n/(n+2))^n is diverges