What is (\partial)/(\partial x)(2xy^5+3x^2y+x^2) ?

The answer to (\partial)/(\partial x)(2xy^5+3x^2y+x^2) is 2y^5+6yx+2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2xy^5+3x^2y+x^2)

\frac{\partial}{\partial x} (2 x y^{5} + 3 x^{2} y + x^{2})

2 y^{5} + 6 y x + 2 x

Solution steps

\frac{\partial}{\partial x} (2 x y^{5} + 3 x^{2} y + x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x y^{5}) + \frac{\partial}{\partial x} (3 x^{2} y) + \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (2 x y^{5}) = 2 y^{5}

\frac{\partial}{\partial x} (3 x^{2} y) = 6 y x

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 2 y^{5} + 6 y x + 2 x

y^{^{''}} + 9 y = 6 tan (3 x)

\int e^{i 6 x} cos (5 x) d x

\int x^{2} (8 x - 3) d x

\int \frac{x ^{3} + 2}{x ^{3}} x - \frac{1}{x ^{2}} d x

\int sin^{6} (5 x) d x

What is (\partial)/(\partial x)(2xy^5+3x^2y+x^2) ?
The answer to (\partial)/(\partial x)(2xy^5+3x^2y+x^2) is 2y^5+6yx+2x