What is the derivative of f(x)=sin(x^2+2x+3) ?

The derivative of f(x)=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)

What is the first derivative of f(x)=sin(x^2+2x+3) ?

The first derivative of f(x)=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)

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derivative of

f (x) = sin (x^{2} + 2 x + 3)

cos (x^{2} + 2 x + 3) (2 x + 2)

Solution steps

\frac{d}{d x} (sin (x^{2} + 2 x + 3))

Apply the chain rule:

cos (x^{2} + 2 x + 3) \frac{d}{d x} (x^{2} + 2 x + 3)

= cos (x^{2} + 2 x + 3) \frac{d}{d x} (x^{2} + 2 x + 3)

\frac{d}{d x} (x^{2} + 2 x + 3) = 2 x + 2

= cos (x^{2} + 2 x + 3) (2 x + 2)

y = 2 x^{2} - 1, [0, 1]

y = \frac{x ^{2}}{2 - x ^{2}}

y^{^{''}} + 4 y = x sin (2 x)

\frac{d}{d x} (6 + 4 x - x^{2})

\frac{d}{d x} (4 2 x - 1)

What is the derivative of f(x)=sin(x^2+2x+3) ?
The derivative of f(x)=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)
What is the first derivative of f(x)=sin(x^2+2x+3) ?
The first derivative of f(x)=sin(x^2+2x+3) is cos(x^2+2x+3)(2x+2)