en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of \sqrt[3]{x}+\sqrt[5]{x}

Solution

\frac{d}{d x} (3 x + 5 x)

Solution

\frac{1}{3 x ^{\frac{2}{3}}} + \frac{1}{5 x ^{\frac{4}{5}}}

Solution steps

\frac{d}{d x} (3 x + 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (5 x)

\frac{d}{d x} (3 x) = \frac{1}{3 x ^{\frac{2}{3}}}

\frac{d}{d x} (5 x) = \frac{1}{5 x ^{\frac{4}{5}}}

= \frac{1}{3 x ^{\frac{2}{3}}} + \frac{1}{5 x ^{\frac{4}{5}}}

Graph

Popular Examples

taylor x/(1+x),1 taylor

\frac{x}{1 + x}, 1

integral from 0 to 9/2 of sqrt(81-x^2)

\int_{0}^{\frac{9}{2}} 81 - x^{2} d x

(dx)/(dt)=0.6-(3x)/(500)

\frac{d x}{d t} = 0.6 - \frac{3 x}{500}

(dy)/(dx)=8x(y-3)

\frac{d y}{d x} = 8 x (y - 3)

integral of 3/4 x^2-5x^2

\int \frac{3}{4} x^{2} - 5 x^{2} d x

Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[3]{x}+\sqrt[5]{x} ?
The derivative of \sqrt[3]{x}+\sqrt[5]{x} is 1/(3x^{2/3)}+1/(5x^{4/5)}
What is the first derivative of \sqrt[3]{x}+\sqrt[5]{x} ?
The first derivative of \sqrt[3]{x}+\sqrt[5]{x} is 1/(3x^{2/3)}+1/(5x^{4/5)}