What is the derivative of y=(3x)/(sqrt(1-x)) ?

The derivative of y=(3x)/(sqrt(1-x)) is (3(2-x))/(2(1-x)sqrt(1-x))

What is the first derivative of y=(3x)/(sqrt(1-x)) ?

The first derivative of y=(3x)/(sqrt(1-x)) is (3(2-x))/(2(1-x)sqrt(1-x))

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derivative of

y = \frac{3 x}{1 - x}

\frac{3 ( 2 - x )}{2 ( 1 - x ) 1 - x}

Solution steps

\frac{d}{d x} (\frac{3 x}{1 - x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{x}{1 - x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 3 \cdot \frac{\frac{d x}{d x} 1 - x - \frac{d}{d x} ( 1 - x ) x}{( 1 - x ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (1 - x) = - \frac{1}{2 1 - x}

= 3 \cdot \frac{1 \cdot 1 - x - ( - \frac{1}{2 1 - x} ) x}{( 1 - x ) ^{2}}

Simplify

3 \cdot \frac{1 \cdot 1 - x - ( - \frac{1}{2 1 - x} ) x}{( 1 - x ) ^{2}} : \frac{3 ( 2 - x )}{2 ( 1 - x ) 1 - x}

= \frac{3 ( 2 - x )}{2 ( 1 - x ) 1 - x}

\frac{\partial}{\partial x} (cosh (y) + x - 2)

\int_{\frac{π}{4}}^{π} (sin (x)) d x

\int_{4}^{\infty} e^{5 x} d x

\int \frac{2 + x ^{2}}{1 + x ^{2}} d x

\int (\frac{x}{2} + \frac{2}{x}) d x

What is the derivative of y=(3x)/(sqrt(1-x)) ?
The derivative of y=(3x)/(sqrt(1-x)) is (3(2-x))/(2(1-x)sqrt(1-x))
What is the first derivative of y=(3x)/(sqrt(1-x)) ?
The first derivative of y=(3x)/(sqrt(1-x)) is (3(2-x))/(2(1-x)sqrt(1-x))