What is (\partial)/(\partial x)(((2xy))/(x^2+y^2)) ?

The answer to (\partial)/(\partial x)(((2xy))/(x^2+y^2)) is (2y(-x^2+y^2))/((x^2+y^2)^2)

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(\partial)/(\partial x)(((2xy))/(x^2+y^2))

\frac{\partial}{\partial x} (\frac{( 2 x y )}{x ^{2} + y ^{2}})

\frac{2 y ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{( 2 x y )}{x ^{2} + y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 y \frac{\partial}{\partial x} (\frac{x}{x ^{2} + y ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 y \frac{\frac{\partial}{\partial x} ( x ) ( x ^{2} + y ^{2} ) - \frac{\partial}{\partial x} ( x ^{2} + y ^{2} ) x}{( x ^{2} + y ^{2} ) ^{2}}

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x^{2} + y^{2}) = 2 x

= 2 y \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 xx}{( x ^{2} + y ^{2} ) ^{2}}

Simplify

2 y \frac{1 \cdot ( x ^{2} + y ^{2} ) - 2 xx}{( x ^{2} + y ^{2} ) ^{2}} : \frac{2 y ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

= \frac{2 y ( - x ^{2} + y ^{2} )}{( x ^{2} + y ^{2} ) ^{2}}

\frac{d}{d x} (\frac{2 - x}{( 3 - x ) ^{4}})

\frac{d}{d x} (5 x e^{- x})

\int_{- 4}^{- 1} - \frac{4}{x ^{3}} d x

y^{^{'}} + 3 y = e^{t}

f (x) = 110 x - 16 x^{2}, at

What is (\partial)/(\partial x)(((2xy))/(x^2+y^2)) ?
The answer to (\partial)/(\partial x)(((2xy))/(x^2+y^2)) is (2y(-x^2+y^2))/((x^2+y^2)^2)