What is the limit as x approaches 6+of (cos((5pi)/6))/(ln(7-x)) ?

The limit as x approaches 6+of (cos((5pi)/6))/(ln(7-x)) is infinity

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limit as x approaches 6+of (cos((5pi)/6))/(ln(7-x))

x \to 6 + lim (\frac{cos ( \frac{5 π}{6} )}{ln ( 7 - x )})

\infty

Solution steps

x \to 6 + lim (\frac{cos ( \frac{5 π}{6} )}{ln ( 7 - x )})

For

x

approaching

6

from the right

, x > 6 \Rightarrow ln (7 - x) < 0

The denominator is a negative quantity approaching 0 from the left

= \infty

H^{\frac{1}{2}}

w \to 3 lim (\frac{( w - 3 )}{( 2 w ^{2} - w - 15 )})

x^{2} y^{^{'}} = x y + 2 x^{2} e^{\frac{y}{x}}

f (x) = - \frac{1}{1 - x}

\frac{\partial}{\partial x} (- sin^{2} (x))

What is the limit as x approaches 6+of (cos((5pi)/6))/(ln(7-x)) ?
The limit as x approaches 6+of (cos((5pi)/6))/(ln(7-x)) is infinity