What is the integral of cos^4(5x) ?

The integral of cos^4(5x) is 1/5 (cos^3(5x)sin(5x)+3/8 (5x-1/4 sin(20x)))+C

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integral of cos^4(5x)

\int cos^{4} (5 x) d x

\frac{1}{5} (cos^{3} (5 x) sin (5 x) + \frac{3}{8} (5 x - \frac{1}{4} sin (20 x))) + C

Solution steps

\int cos^{4} (5 x) d x

Apply u-substitution

: \int cos^{4} (u) \frac{1}{5} d u

= \int cos^{4} (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int cos^{4} (u) d u

Simplify

cos^{4} (u) : cos^{3} (u) cos (u)

= \frac{1}{5} \cdot \int cos^{3} (u) cos (u) d u

Apply Integration By Parts

: cos^{3} (u) sin (u) - \int - 3 cos^{2} (u) sin^{2} (u) d u

= \frac{1}{5} (cos^{3} (u) sin (u) - \int - 3 cos^{2} (u) sin^{2} (u) d u)

\int - 3 cos^{2} (u) sin^{2} (u) d u = - \frac{3}{8} (u - \frac{1}{4} sin (4 u))

= \frac{1}{5} (cos^{3} (u) sin (u) - (- \frac{3}{8} (u - \frac{1}{4} sin (4 u))))

Substitute back

u = 5 x

= \frac{1}{5} (cos^{3} (5 x) sin (5 x) - (- \frac{3}{8} (5 x - \frac{1}{4} sin (4 \cdot 5 x))))

Simplify

= \frac{1}{5} (cos^{3} (5 x) sin (5 x) + \frac{3}{8} (5 x - \frac{1}{4} sin (20 x)))

Add a constant to the solution

= \frac{1}{5} (cos^{3} (5 x) sin (5 x) + \frac{3}{8} (5 x - \frac{1}{4} sin (20 x))) + C

\frac{d}{d x} (sin (2 x) + 10)

\frac{5}{x ^{2}}

\int_{0}^{1.75} 1250 x d x

y^{^{'}} + 3 y = x^{2}

\frac{d}{d x} (\frac{x}{( x + 1 ) ^{2}})

What is the integral of cos^4(5x) ?
The integral of cos^4(5x) is 1/5 (cos^3(5x)sin(5x)+3/8 (5x-1/4 sin(20x)))+C