What is (\partial)/(\partial y)(y^2-2xy+6x) ?

The answer to (\partial)/(\partial y)(y^2-2xy+6x) is 2y-2x

Popular >

(\partial)/(\partial y)(y^2-2xy+6x)

\frac{\partial}{\partial y} (y^{2} - 2 x y + 6 x)

2 y - 2 x

Solution steps

\frac{\partial}{\partial y} (y^{2} - 2 x y + 6 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) - \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (6 x)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (6 x) = 0

= 2 y - 2 x + 0

Simplify

= 2 y - 2 x

\int_{0}^{1} \frac{x}{e ^{x^{2}}} d x

\frac{\partial}{\partial y} (\frac{a x}{y ^{2}})

\int \frac{1}{cos ( 8 x )} d x

\int_{0}^{2} 6 x (2 - x) d x

(2 x - 3) e^{2 - x}

What is (\partial)/(\partial y)(y^2-2xy+6x) ?
The answer to (\partial)/(\partial y)(y^2-2xy+6x) is 2y-2x