What is (\partial)/(\partial x)(x-cos(x)) ?

The answer to (\partial)/(\partial x)(x-cos(x)) is 1+sin(x)

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(\partial)/(\partial x)(x-cos(x))

\frac{\partial}{\partial x} (x - cos (x))

1 + sin (x)

Solution steps

\frac{\partial}{\partial x} (x - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (cos (x))

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 1 - (- sin (x))

Simplify

= 1 + sin (x)

y^{^{'}} = y x

x \to 0 lim (+ \frac{x ^{3} + 3}{x})

\frac{d}{d x} (ln (3 - x^{2}))

\frac{d}{d x} (24 + x^{2})

n \to \infty lim (2 n^{2})

What is (\partial)/(\partial x)(x-cos(x)) ?
The answer to (\partial)/(\partial x)(x-cos(x)) is 1+sin(x)