What is the limit as x approaches 1-of 6/(x^3-1) ?

The limit as x approaches 1-of 6/(x^3-1) is -infinity

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limit as x approaches 1-of 6/(x^3-1)

x \to 1 - lim (\frac{6}{x ^{3} - 1})

- \infty

Solution steps

x \to 1 - lim (\frac{6}{x ^{3} - 1})

For

x

approaching

1

from the left

, x < 1 \Rightarrow x^{3} - 1 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

x \to 0 + lim (tan^{x} (2 x))

\frac{\partial}{\partial z} (2 z e^{x yz})

9 y^{^{''}} + 48 y^{^{'}} + 64 y = 0

f^{^{'}} (x) = - x

\frac{d}{d x} ((arctan (9 x))^{2})

What is the limit as x approaches 1-of 6/(x^3-1) ?
The limit as x approaches 1-of 6/(x^3-1) is -infinity