What is the d/(dt)(acos(10t)+bsin(10t)) ?

The d/(dt)(acos(10t)+bsin(10t)) is -10asin(10t)+bcos(10t)*10

What is the first d/(dt)(acos(10t)+bsin(10t)) ?

The first d/(dt)(acos(10t)+bsin(10t)) is -10asin(10t)+bcos(10t)*10

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\frac{d}{d t} (a cos (10 t) + b sin (10 t))

- 10 a sin (10 t) + b cos (10 t) \cdot 10

Solution steps

\frac{d}{d t} (a cos (10 t) + b sin (10 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (a cos (10 t)) + \frac{d}{d t} (b sin (10 t))

\frac{d}{d t} (a cos (10 t)) = - 10 a sin (10 t)

\frac{d}{d t} (b sin (10 t)) = b cos (10 t) \cdot 10

= - 10 a sin (10 t) + b cos (10 t) \cdot 10

\int_{0}^{1} (\frac{1}{x}) d x

\frac{d}{d x} (89 x)

\frac{6 x}{x + 5}

\int e^{x} 41 + e^{x} d x

cos^{2} (e^{c o s^{2} (t)})

What is the d/(dt)(acos(10t)+bsin(10t)) ?
The d/(dt)(acos(10t)+bsin(10t)) is -10asin(10t)+bcos(10t)*10
What is the first d/(dt)(acos(10t)+bsin(10t)) ?
The first d/(dt)(acos(10t)+bsin(10t)) is -10asin(10t)+bcos(10t)*10