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Popular >

derivative of \sqrt[7]{t}+4sqrt(t^7)

Solution

derivative of

Solution

\frac{1 + 98 t ^{\frac{47}{14}}}{7 t ^{\frac{6}{7}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (4 t^{7}) = 14 t^{\frac{5}{2}}

= \frac{1}{7 t ^{\frac{6}{7}}} + 14 t^{\frac{5}{2}}

Simplify

\frac{1}{7 t ^{\frac{6}{7}}} + 14 t^{\frac{5}{2}} : \frac{1 + 98 t ^{\frac{47}{14}}}{7 t ^{\frac{6}{7}}}

= \frac{1 + 98 t ^{\frac{47}{14}}}{7 t ^{\frac{6}{7}}}

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Frequently Asked Questions (FAQ)

What is the derivative of \sqrt[7]{t}+4sqrt(t^7) ?
The derivative of \sqrt[7]{t}+4sqrt(t^7) is (1+98t^{47/14})/(7t^{6/7)}
What is the first derivative of \sqrt[7]{t}+4sqrt(t^7) ?
The first derivative of \sqrt[7]{t}+4sqrt(t^7) is (1+98t^{47/14})/(7t^{6/7)}