What is the derivative of |x^3-3x^2+2| ?

The derivative of |x^3-3x^2+2| is ((x^3-3x^2+2)(3x^2-6x))/(|x^3-3x^2+2|)

What is the first derivative of |x^3-3x^2+2| ?

The first derivative of |x^3-3x^2+2| is ((x^3-3x^2+2)(3x^2-6x))/(|x^3-3x^2+2|)

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\frac{d}{d x} (x^{3} - 3 x^{2} + 2)

\frac{( x ^{3} - 3 x ^{2} + 2 ) ( 3 x ^{2} - 6 x )}{∣ x ^{3} - 3 x ^{2} + 2 ∣}

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 2)

Apply the chain rule:

\frac{x ^{3} - 3 x ^{2} + 2}{∣ ( x ^{3} - 3 x ^{2} + 2 ) ∣} \frac{d}{d x} (x^{3} - 3 x^{2} + 2)

= \frac{x ^{3} - 3 x ^{2} + 2}{∣ ( x ^{3} - 3 x ^{2} + 2 ) ∣} \frac{d}{d x} (x^{3} - 3 x^{2} + 2)

\frac{d}{d x} (x^{3} - 3 x^{2} + 2) = 3 x^{2} - 6 x

= \frac{x ^{3} - 3 x ^{2} + 2}{∣ ( x ^{3} - 3 x ^{2} + 2 ) ∣} (3 x^{2} - 6 x)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{3} - 3 x ^{2} + 2 ) ( 3 x ^{2} - 6 x )}{∣ x ^{3} - 3 x ^{2} + 2 ∣}

y = x^{2} - 2, (- 3, 7)

3 x y^{^{'}} = y^{2} - y - 2

f (x) = ln (3 x)

\int \frac{1}{( 4 - x ^{2} )} d x

\int (1 - x)^{\frac{1}{2}} d x

What is the derivative of |x^3-3x^2+2| ?
The derivative of |x^3-3x^2+2| is ((x^3-3x^2+2)(3x^2-6x))/(|x^3-3x^2+2|)
What is the first derivative of |x^3-3x^2+2| ?
The first derivative of |x^3-3x^2+2| is ((x^3-3x^2+2)(3x^2-6x))/(|x^3-3x^2+2|)