What is the sum from n=-4 to infinity of (-4/7)^n ?

The sum from n=-4 to infinity of (-4/7)^n is converges

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sum from n=-4 to infinity of (-4/7)^n

n = - 4 \sum \infty (- \frac{4}{7})^{n}

converges

Solution steps

n = - 4 \sum \infty (- \frac{4}{7})^{n}

Apply Series Ratio Test:

converges

= converges

\int \frac{1}{( 1 - 2 x ) ^{4} 4 x ^{2} - 4 x - 4} d x

\frac{d}{d x} (\frac{3}{1 + 3 x})

\int \frac{4}{65} x^{3} d x

\int \frac{1}{x ^{2} + a x} d x

f (x) = 2 x, (0, 3)

What is the sum from n=-4 to infinity of (-4/7)^n ?
The sum from n=-4 to infinity of (-4/7)^n is converges