What is (\partial)/(\partial y)(e^x+y) ?

The answer to (\partial)/(\partial y)(e^x+y) is 1

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(\partial)/(\partial y)(e^x+y)

\frac{\partial}{\partial y} (e^{x} + y)

1

Solution steps

\frac{\partial}{\partial y} (e^{x} + y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (e^{x}) + \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (e^{x}) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 + 1

Simplify

= 1

\frac{\partial}{\partial x} (x^{2} - 5 x y + 3 y^{2} + x - 4 y)

\int (x x^{4}) d x

\frac{d}{d x} (\frac{1}{2} ln (\frac{1 + x}{1 - x}))

y^{^{'''}} - 5 y^{^{''}} + 8 y^{^{'}} + 14 y = 0

\int \frac{12 x ^{3} + 6 x ^{2}}{3 x ^{4} + 2 x ^{3} - 5} d x

What is (\partial)/(\partial y)(e^x+y) ?
The answer to (\partial)/(\partial y)(e^x+y) is 1