What is the tangent of y=x^2-6 ?

The tangent of y=x^2-6 is y=2a_{0}x-a_{0}^2-6

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tangent of y=x^2-6

tangent of

y = x^{2} - 6

y = 2 a_{0} x - a_{0}^{2} - 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} - 6)

Find the slope of

y = x^{2} - 6 : \frac{d y}{d x} = 2 x

Compute the slope of

y = x^{2} - 6

x = a_{0} : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} - 6) : y = 2 a_{0} x - a_{0}^{2} - 6

y = 2 a_{0} x - a_{0}^{2} - 6

x \to \infty lim (0 + x)

\frac{d}{d c} (\frac{sin ( 2 c )}{2 - cos ( 2 c )})

\int \frac{3}{1 - 9 x ^{2}} d x

\int (x^{2} - 3 x - 4) d x

f (x) = x + 4, (12, 4)