What is the solution for (dy)/(dt)=(t^2+ty+y^2)/(t^2) ?

The solution for (dy)/(dt)=(t^2+ty+y^2)/(t^2) is y=tan(ln(t)+c_{1})t

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(dy)/(dt)=(t^2+ty+y^2)/(t^2)

\frac{d y}{d t} = \frac{t ^{2} + t y + y ^{2}}{t ^{2}}

y = tan (ln (t) + c_{1}) t

Solution steps

\frac{d y}{d t} = \frac{t ^{2} + t y + y ^{2}}{t ^{2}}

Solve using substitution:

y = tan (ln (t) + c_{1}) t

y = tan (ln (t) + c_{1}) t

n = 0 \sum \infty n (n + 1)

\int_{4}^{9} \frac{1}{x ^{2} - 1} d x

\int_{0}^{1} 4 e^{7 x} d x

1 - 6 x^{2} y^{^{'}} = x

x = - 2, y = x + 2, y = x^{2}

What is the solution for (dy)/(dt)=(t^2+ty+y^2)/(t^2) ?
The solution for (dy)/(dt)=(t^2+ty+y^2)/(t^2) is y=tan(ln(t)+c_{1})t