What is the solution for y^'=8x^6y-y,y(1)=-4 ?

The solution for y^'=8x^6y-y,y(1)=-4 is y=-4/(\sqrt[7]{e)e^{(-8x^7+7x)/7}}

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y^'=8x^6y-y,y(1)=-4

y^{^{'}} = 8 x^{6} y - y, y (1) = - 4

Solution steps

y^{'} (x) = 8 x^{6} y - y

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What is the solution for y^'=8x^6y-y,y(1)=-4 ?
The solution for y^'=8x^6y-y,y(1)=-4 is y=-4/(\sqrt[7]{e)e^{(-8x^7+7x)/7}}