What is the tangent of f(x)=sqrt(x+5),\at x=-4 ?

The tangent of f(x)=sqrt(x+5),\at x=-4 is y= 1/2 x+3

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tangent of f(x)=sqrt(x+5),\at x=-4

tangent of

f (x) = x + 5, at x = - 4

y = \frac{1}{2} x + 3

Solution steps

Find the tangent point:

(- 4, 1)

Find the slope of

f (x) = x + 5 : \frac{df ( x )}{d x} = \frac{1}{2 x + 5}

Compute the slope of

f (x) = x + 5

x = - 4 : m = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(- 4, 1) : y = \frac{1}{2} x + 3

y = \frac{1}{2} x + 3

\int tan^{2} (5 x) sec^{4} (5 x) d x

\frac{d}{d t} (\frac{( t + 1 ) ^{2}}{( t - 1 ) ^{2}})

\int sin (wt - b x) d t

\frac{\partial}{\partial y} (2 x^{2} + 6 x y + y^{2})

c cos (t) + t^{2} sin (t)

What is the tangent of f(x)=sqrt(x+5),\at x=-4 ?
The tangent of f(x)=sqrt(x+5),\at x=-4 is y= 1/2 x+3