What is the derivative of e^{-x}+e^x ?

The derivative of e^{-x}+e^x is -e^{-x}+e^x

What is the first derivative of e^{-x}+e^x ?

The first derivative of e^{-x}+e^x is -e^{-x}+e^x

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\frac{d}{d x} (e^{- x} + e^{x})

- e^{- x} + e^{x}

Solution steps

\frac{d}{d x} (e^{- x} + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{- x}) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (e^{- x}) = - e^{- x}

\frac{d}{d x} (e^{x}) = e^{x}

= - e^{- x} + e^{x}

n = 4 \sum \infty \frac{1}{n ^{2} + n}

x \to 3 lim (\frac{x + 2}{x - 3})

x \to 9 + lim (\frac{x - 9}{∣ x - 9 ∣})

y^{^{''}} + 6 y^{^{'}} + 9 y = 12 e^{- x}

\frac{d}{d x} (cos (\frac{1 - e ^{8 x}}{1 + e ^{8 x}}))

What is the derivative of e^{-x}+e^x ?
The derivative of e^{-x}+e^x is -e^{-x}+e^x
What is the first derivative of e^{-x}+e^x ?
The first derivative of e^{-x}+e^x is -e^{-x}+e^x