What is (\partial)/(\partial y)(ln(y^2)) ?

The answer to (\partial)/(\partial y)(ln(y^2)) is 2/y

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(\partial)/(\partial y)(ln(y^2))

\frac{\partial}{\partial y} (ln (y^{2}))

\frac{2}{y}

Solution steps

\frac{\partial}{\partial y} (ln (y^{2}))

Apply the chain rule:

\frac{1}{y ^{2}} \frac{\partial}{\partial y} (y^{2})

= \frac{1}{y ^{2}} \frac{\partial}{\partial y} (y^{2})

\frac{\partial}{\partial y} (y^{2}) = 2 y

= \frac{1}{y ^{2}} \cdot 2 y

Simplify

\frac{1}{y ^{2}} \cdot 2 y : \frac{2}{y}

= \frac{2}{y}

f (x) = - \frac{1}{x}

(x + 3)^{\frac{1}{2}}

\int cos (\frac{z}{y}) d z

f (x) = - 3 x^{2} - 2 x^{2} - 1, at x = - 1

\int \frac{cos ( x )}{5 + sin ( x )} d x

What is (\partial)/(\partial y)(ln(y^2)) ?
The answer to (\partial)/(\partial y)(ln(y^2)) is 2/y