What is (\partial)/(\partial z)(2xyz) ?

The answer to (\partial)/(\partial z)(2xyz) is 2xy

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(\partial)/(\partial z)(2xyz)

\frac{\partial}{\partial z} (2 x yz)

2 x y

Solution steps

\frac{\partial}{\partial z} (2 x yz)

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x y \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= 2 x y \cdot 1

Simplify

= 2 x y

6 x^{2} y^{^{'}} = y^{^{'}} + 3 x e^{- y}

\frac{d}{d x} (- \frac{1}{2} + \frac{7}{5} x^{3})

\frac{d}{d x} ((x^{3} - 2 x^{2} + 3) (7 x^{2} - 4 x))

\frac{d}{d y} (k y (1 - \frac{y}{N}) (\frac{y}{M} - 1))

\frac{d P}{d t} + P = 10, P (0) = 4

What is (\partial)/(\partial z)(2xyz) ?
The answer to (\partial)/(\partial z)(2xyz) is 2xy