What is the derivative of sin^7(θ) ?

The derivative of sin^7(θ) is 7sin^6(θ)cos(θ)

What is the first derivative of sin^7(θ) ?

The first derivative of sin^7(θ) is 7sin^6(θ)cos(θ)

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derivative of

sin^{7} (θ)

7 sin^{6} (θ) cos (θ)

Solution steps

\frac{d}{d θ} (sin^{7} (θ))

Apply the chain rule:

7 (sin (θ))^{6} \frac{d}{d θ} (sin (θ))

= 7 (sin (θ))^{6} \frac{d}{d θ} (sin (θ))

\frac{d}{d θ} (sin (θ)) = cos (θ)

= 7 (sin (θ))^{6} cos (θ)

Simplify

= 7 sin^{6} (θ) cos (θ)

\frac{6}{s} + 16 (\frac{1}{s ^{2} + 16})

\frac{\partial}{\partial y} (x x^{2} + y^{2})

\frac{d}{d x} (cos (x) + 2 sin (x))

\int \frac{- 2 x}{x ^{2} - 1} d x

\frac{\partial}{\partial y} (8 y - (x + y)^{3})

What is the derivative of sin^7(θ) ?
The derivative of sin^7(θ) is 7sin^6(θ)cos(θ)
What is the first derivative of sin^7(θ) ?
The first derivative of sin^7(θ) is 7sin^6(θ)cos(θ)