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Popular >

x^2y^{''}-4xy^'+4y=0

Solution

x^{2} y^{^{''}} - 4 x y^{^{'}} + 4 y = 0

Solution

y = c_{1} x^{4} + c_{2} x

Solution steps

x^{2} y^{''} (x) - 4 x y^{'} (x) + 4 y = 0

Solve linear ODE:

y = c_{1} x^{4} + c_{2} x

y = c_{1} x^{4} + c_{2} x

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f (t) = t + t

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\int \frac{3}{x + 2} d x

Frequently Asked Questions (FAQ)

What is the solution for x^2y^{''}-4xy^'+4y=0 ?
The solution for x^2y^{''}-4xy^'+4y=0 is y=c_{1}x^4+c_{2}x