What is the limit as t approaches 0 of 3/t-3/(t^2+t) ?

The limit as t approaches 0 of 3/t-3/(t^2+t) is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as t approaches 0 of 3/t-3/(t^2+t)

t \to 0 lim (\frac{3}{t} - \frac{3}{t ^{2} + t})

3

Solution steps

t \to 0 lim (\frac{3}{t} - \frac{3}{t ^{2} + t})

Simplify

\frac{3}{t} - \frac{3}{t ^{2} + t} : \frac{3}{t + 1}

= t \to 0 lim (\frac{3}{t + 1})

Plug in the value

t = 0

= \frac{3}{0 + 1}

Simplify

= 3

\int \frac{4}{x ^{5}} - \frac{3}{x ^{4}} d x

\int_{- 1}^{1} \frac{3 x}{( x + 7 ) ^{2}} d x

\frac{\partial}{\partial y} (cos (\frac{x}{y}))

\frac{x ^{3}}{16 - x ^{2}} d x

\int \frac{5}{2 x} d x

What is the limit as t approaches 0 of 3/t-3/(t^2+t) ?
The limit as t approaches 0 of 3/t-3/(t^2+t) is 3