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Popular >

xy^'-2y=x^4,y(1)=0

Solution

x y^{^{'}} - 2 y = x^{4}, y (1) = 0

Solution

y = \frac{x ^{4}}{2} - \frac{x ^{2}}{2}

Solution steps

x y^{'} (x) - 2 y = x^{4}

Solve linear ODE:

y = \frac{x ^{4}}{2} - \frac{x ^{2}}{2}

y = \frac{x ^{4}}{2} - \frac{x ^{2}}{2}

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Frequently Asked Questions (FAQ)

What is the solution for xy^'-2y=x^4,y(1)=0 ?
The solution for xy^'-2y=x^4,y(1)=0 is y=(x^4)/2-(x^2)/2