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Popular >

x^2y^'-3xy-2y^2=0

Solution

x^{2} y^{^{'}} - 3 x y - 2 y^{2} = 0

Solution

y = \frac{x ^{3}}{- x ^{2} + c _{1}}

Solution steps

x^{2} y^{'} (x) - 3 x y - 2 y^{2} = 0

Solve Bernoulli ODE:

y = \frac{x ^{3}}{- x ^{2} + c _{1}}

y = \frac{x ^{3}}{- x ^{2} + c _{1}}

Popular Examples

(dy)/(dt)+2/t y=t-1+y/t

\frac{d y}{d t} + \frac{2}{t} y = t - 1 + \frac{y}{t}

tangent of y=9x^{5/2}-7x^{3/2},\at x=4 tangent of

y = 9 x^{\frac{5}{2}} - 7 x^{\frac{3}{2}}, at x = 4

(dy)/(dx)-2(x+1)^3= 4/((x+1))y

\frac{d y}{d x} - 2 (x + 1)^{3} = \frac{4}{( x + 1 )} y

derivative of f(x)=arctan(pi/x)derivative of

f (x) = arctan (\frac{π}{x})

y^{^{'}} = 6 y^{2} sin (x)

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-3xy-2y^2=0 ?
The solution for x^2y^'-3xy-2y^2=0 is y=(x^3)/(-x^2+c_{1)}