What is the tangent of sqrt(5x+6),\at x=6 ?

The tangent of sqrt(5x+6),\at x=6 is y= 5/12 x+7/2

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tangent of sqrt(5x+6),\at x=6

tangent of

5 x + 6, at x = 6

y = \frac{5}{12} x + \frac{7}{2}

Solution steps

Find the tangent point:

(6, 6)

Find the slope of

y = 5 x + 6 : \frac{d y}{d x} = \frac{5}{2 5 x + 6}

Compute the slope of

y = 5 x + 6

x = 6 : m = \frac{5}{12}

Find the line with slope m=

\frac{5}{12}

and passing through

(6, 6) : y = \frac{5}{12} x + \frac{7}{2}

y = \frac{5}{12} x + \frac{7}{2}

\int x e^{- s x} d x

\frac{\partial}{\partial x} (8 x^{5} y^{3} - 9 x^{4} y^{6})

\frac{d}{d x} (\frac{4 x ^{3} + 1}{x ^{2} - x + 3})

\frac{d y}{d x} - \frac{y}{x} = \frac{x ^{2} + y ^{2}}{x}

f (x) = e^{\frac{1}{2} x}

What is the tangent of sqrt(5x+6),\at x=6 ?
The tangent of sqrt(5x+6),\at x=6 is y= 5/12 x+7/2