What is the integral from 0 to infinity of e^{-0.2x} ?

The integral from 0 to infinity of e^{-0.2x} is 5

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integral from 0 to infinity of e^{-0.2x}

\int_{0}^{\infty} e^{- 0.2 x} d x

5

Solution steps

\int_{0}^{\infty} e^{- 0.2 x} d x

Compute the indefinite integral:

\int e^{- 0.2 x} d x = - 5 e^{- 0.2 x} + C

Compute the boundaries:

\int_{0}^{\infty} e^{- 0.2 x} d x = 0 - (- 5)

= 0 - (- 5)

Simplify

= 5

\int 1 0^{- 3 x} d x

\frac{d}{d x} ((e^{x})^{3})

\frac{d}{d x} ((x - 1)^{2} sin (\frac{1}{x - 1}))

\frac{x ^{2} + 2 x - 6}{( x + 1 ) ^{2}}

\frac{4}{x}

What is the integral from 0 to infinity of e^{-0.2x} ?
The integral from 0 to infinity of e^{-0.2x} is 5