What is the f(x)= 1/(x^2+4) ?

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f(x)= 1/(x^2+4)

f (x) = \frac{1}{x ^{2} + 4}

Domain : - \infty < x < \infty

Range : 0 < f (x) \leq \frac{1}{4}

Y Intercepts : (0, \frac{1}{4})

Asymptotes : Horizontal y = 0

Extreme Points : Maximum (0, \frac{1}{4})

Interval Notation

Domain : (- \infty, \infty)

Range : (0, \frac{1}{4}]

Solution steps

Domain of

\frac{1}{x ^{2} + 4} : - \infty < x < \infty

Range of

\frac{1}{x ^{2} + 4} : 0 < f (x) \leq \frac{1}{4}

Axis interception points of

\frac{1}{x ^{2} + 4} :

Y Intercepts

: (0, \frac{1}{4})

Asymptotes of

\frac{1}{x ^{2} + 4} :

Horizontal

: y = 0

Extreme Points of

\frac{1}{x ^{2} + 4} :

Maximum

(0, \frac{1}{4})

f (x) = \frac{5 x}{x ^{2} - 4}, at x = 3

x \to 6 lim (x - 6)

\int - 2 tan (x) d x

x \to + 0 lim (\frac{x ^{4}}{x ^{4}})

\int e^{5 x} cos (4 x) d x