What is the slope ofintercept (7,0),(-1,2) ?

The slope ofintercept (7,0),(-1,2) is y=-1/4 x+7/4

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slope ofintercept (7,0),(-1,2)

slope intercept

(7, 0), (- 1, 2)

y = - \frac{1}{4} x + \frac{7}{4}

Solution steps

Compute the slope

(7, 0), (- 1, 2) : m = - \frac{1}{4}

Compute the

y

intercept:

b = \frac{7}{4}

Construct the line equation

y = mx + b

where

m = - \frac{1}{4}

and

b = \frac{7}{4}

y = - \frac{1}{4} x + \frac{7}{4}

e^{- (t - 3)^{2}}

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\frac{d}{d y} (cos (x^{2}) - y)

\int_{- 4}^{6} 6 d x

What is the slope ofintercept (7,0),(-1,2) ?
The slope ofintercept (7,0),(-1,2) is y=-1/4 x+7/4