What is implicit (dy)/(dx),y^2-x=0 ?

The answer to implicit (dy)/(dx),y^2-x=0 is (dy)/(dx)= 1/(2y)

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implicit (dy)/(dx),y^2-x=0

implicit derivative

\frac{d y}{d x}, y^{2} - x = 0

\frac{d y}{d x} = \frac{1}{2 y}

Solution steps

y^{2} - x = 0

Treat

y

y (x)

Differentiate both sides:

2 y \frac{d y}{d x} - 1 = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1}{2 y}

\frac{d y}{d x} = \frac{1}{2 y}

\int \frac{x ^{3} + x + 1}{x ^{2} + 2 x + 1} d x

\int_{2}^{\infty} \frac{ln ( x )}{x} d x

\frac{d}{d x} (- 6 x y)

\int_{1}^{2} 9 x^{4} ln (x) d x

\int \frac{6}{6 + e ^{x}} d x

What is implicit (dy)/(dx),y^2-x=0 ?
The answer to implicit (dy)/(dx),y^2-x=0 is (dy)/(dx)= 1/(2y)