What is the derivative of-1/(4x^{3/2}) ?

The derivative of-1/(4x^{3/2}) is 3/(8x^{5/2)}

What is the first derivative of-1/(4x^{3/2}) ?

The first derivative of-1/(4x^{3/2}) is 3/(8x^{5/2)}

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\frac{d}{d x} (- \frac{1}{4 x ^{\frac{3}{2}}})

\frac{3}{8 x ^{\frac{5}{2}}}

Solution steps

\frac{d}{d x} (- \frac{1}{4 x ^{\frac{3}{2}}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{1}{4} \frac{d}{d x} (\frac{1}{x ^{\frac{3}{2}}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - \frac{1}{4} \frac{d}{d x} (x^{- \frac{3}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{4} (- \frac{3}{2} x^{- \frac{3}{2} - 1})

Simplify

- \frac{1}{4} (- \frac{3}{2} x^{- \frac{3}{2} - 1}) : \frac{3}{8 x ^{\frac{5}{2}}}

= \frac{3}{8 x ^{\frac{5}{2}}}

\int e^{5 x + 3} d x

\int \frac{2 ^{t a n (x)}}{cos ^{2} ( x )} d x

x \to - 6 lim (\frac{x ^{2} - 2}{6 - x})

\frac{d y}{d x} = y (10 - y) - 9

\frac{d}{d x} (\frac{e ^{- x}}{1 + e ^{- x}})

What is the derivative of-1/(4x^{3/2}) ?
The derivative of-1/(4x^{3/2}) is 3/(8x^{5/2)}
What is the first derivative of-1/(4x^{3/2}) ?
The first derivative of-1/(4x^{3/2}) is 3/(8x^{5/2)}