What is the derivative of 3/(sqrt(t)) ?

The derivative of 3/(sqrt(t)) is -3/(2t^{3/2)}

What is the first derivative of 3/(sqrt(t)) ?

The first derivative of 3/(sqrt(t)) is -3/(2t^{3/2)}

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derivative of

\frac{3}{t}

- \frac{3}{2 t ^{\frac{3}{2}}}

Solution steps

\frac{d}{d t} (\frac{3}{t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d t} (t^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- \frac{1}{2} t^{- \frac{1}{2} - 1})

Simplify

3 (- \frac{1}{2} t^{- \frac{1}{2} - 1}) : - \frac{3}{2 t ^{\frac{3}{2}}}

= - \frac{3}{2 t ^{\frac{3}{2}}}

\int_{4}^{5} \frac{1}{x ^{2} - 1} d x

\frac{\partial}{\partial x} (x \cdot ln (x))

\int 2 π y (8 - y^{\frac{3}{2}}) d y

f (x) = (ln (x))^{3}, at x = 11

f (x) = x^{3} + 2 x, at x = 1

What is the derivative of 3/(sqrt(t)) ?
The derivative of 3/(sqrt(t)) is -3/(2t^{3/2)}
What is the first derivative of 3/(sqrt(t)) ?
The first derivative of 3/(sqrt(t)) is -3/(2t^{3/2)}