en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y=4x,y=x^3+3x^2

Solution

area

y = 4 x, y = x^{3} + 3 x^{2}

Solution

\frac{131}{4}

+1

Decimal Notation

32.75

Solution steps

Apply the area formula:

\int_{- 4}^{1} 4 x - (x^{3} + 3 x^{2}) d x

Solve

\int_{- 4}^{1} 4 x - (x^{3} + 3 x^{2}) d x : \frac{131}{4}

The area is:

= \frac{131}{4}

Popular Examples

integral from 0 to 1 of 2/7 x^2(x+3)

\int_{0}^{1} \frac{2}{7} x^{2} (x + 3) d x

integral from 0 to 1 of pi(5x^6-5x)^2

\int_{0}^{1} π (5 x^{6} - 5 x)^{2} d x

integral from 0 to 10 of xe^{-x}

\int_{0}^{10} x e^{- x} d x

xyy^'+y^2=xe^{-x}

x y y^{^{'}} + y^{2} = x e^{- x}

integral from 0 to b of e^{ux}a(b-x)

\int_{0}^{b} e^{ux} a (b - x) d x

Frequently Asked Questions (FAQ)

What is area y=4x,y=x^3+3x^2 ?
The answer to area y=4x,y=x^3+3x^2 is 131/4