What is (\partial)/(\partial y)(y^2+1) ?

The answer to (\partial)/(\partial y)(y^2+1) is 2y

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(\partial)/(\partial y)(y^2+1)

\frac{\partial}{\partial y} (y^{2} + 1)

2 y

Solution steps

\frac{\partial}{\partial y} (y^{2} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (1) = 0

= 2 y + 0

Simplify

= 2 y

y^{^{''}} + 2 y^{^{'}} + y = 2 e^{- t}, y (0) = - 1, y^{^{'}} (0) = 3

g (x) = x^{\frac{5}{2}}

\int_{0}^{\infty} \frac{1}{4 + x ^{2}} d x

\frac{d}{d x} (e^{x} + x)

\frac{d}{d x} (9 x^{2} cos (x) cot (x))

What is (\partial)/(\partial y)(y^2+1) ?
The answer to (\partial)/(\partial y)(y^2+1) is 2y