What is the integral of sqrt(x)-7cos(x) ?

The integral of sqrt(x)-7cos(x) is 2/3 x^{3/2}-7sin(x)+C

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integral of sqrt(x)-7cos(x)

\int x - 7 cos (x) d x

\frac{2}{3} x^{\frac{3}{2}} - 7 sin (x) + C

Solution steps

\int x - 7 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int 7 cos (x) d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int 7 cos (x) d x = 7 sin (x)

= \frac{2}{3} x^{\frac{3}{2}} - 7 sin (x)

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} - 7 sin (x) + C

\int sin^{2} (\frac{3 x}{2}) d x

y = \frac{4}{x}

\int 12 (x - 4)^{5} d x

9 x - 36

What is the integral of sqrt(x)-7cos(x) ?
The integral of sqrt(x)-7cos(x) is 2/3 x^{3/2}-7sin(x)+C