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Popular >

integral of 1/(4x^5)

Solution

\int \frac{1}{4 x ^{5}} d x

Solution

- \frac{1}{16 x ^{4}} + C

Solution steps

\int \frac{1}{4 x ^{5}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int \frac{1}{x ^{5}} d x

Apply the Power Rule

: - \frac{1}{4 x ^{4}}

= \frac{1}{4} (- \frac{1}{4 x ^{4}})

Simplify

\frac{1}{4} (- \frac{1}{4 x ^{4}}) : - \frac{1}{16 x ^{4}}

= - \frac{1}{16 x ^{4}}

Add a constant to the solution

= - \frac{1}{16 x ^{4}} + C

Popular Examples

integral of (2-x)^5

\int (2 - x)^{5} d x

integral from 0 to 9 of xsqrt(81-x^2)

\int_{0}^{9} x 81 - x^{2} d x

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\frac{d}{d x} (e^{2 x} + 2)

inverse oflaplace (s^2)/(s+1)inverse laplace

\frac{s ^{2}}{s + 1}

xy^'=y+2x^2sin(x),y(pi)=0

x y^{^{'}} = y + 2 x^{2} sin (x), y (π) = 0

Frequently Asked Questions (FAQ)

What is the integral of 1/(4x^5) ?
The integral of 1/(4x^5) is -1/(16x^4)+C