What is the sum from n=1 to infinity of (e^n)/(n^2) ?

The sum from n=1 to infinity of (e^n)/(n^2) is diverges

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sum from n=1 to infinity of (e^n)/(n^2)

n = 1 \sum \infty \frac{e ^{n}}{n ^{2}}

diverges

Solution steps

n = 1 \sum \infty \frac{e ^{n}}{n ^{2}}

Apply Series Ratio Test:

diverges

= diverges

\frac{\partial}{\partial x} (2 x^{3} + 3 y^{3} - 12 x y)

\int \frac{1}{( x ^{2} - 6 x ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (x y E (x, y) (x, y)^{\frac{x}{y}})

\int - 2 cos^{2} (x) d x

f (x) = 2 sec (3 x^{2})

What is the sum from n=1 to infinity of (e^n)/(n^2) ?
The sum from n=1 to infinity of (e^n)/(n^2) is diverges