What is the derivative of x/(10-(10)/x) ?

The derivative of x/(10-(10)/x) is 1/10+(10)/(x^2)

What is the first derivative of x/(10-(10)/x) ?

The first derivative of x/(10-(10)/x) is 1/10+(10)/(x^2)

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\frac{d}{d x} (\frac{x}{10} - \frac{10}{x})

\frac{1}{10} + \frac{10}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{10} - \frac{10}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{10}) - \frac{d}{d x} (\frac{10}{x})

\frac{d}{d x} (\frac{x}{10}) = \frac{1}{10}

\frac{d}{d x} (\frac{10}{x}) = - \frac{10}{x ^{2}}

= \frac{1}{10} - (- \frac{10}{x ^{2}})

Simplify

= \frac{1}{10} + \frac{10}{x ^{2}}

\int 20 θ sec^{2} (θ) d θ

\int \frac{\frac{d}{1} ( x )}{x} d x

\frac{d}{d x} (\frac{x}{a ^{2} + x ^{2}})

\frac{d}{d x} (16 x + 1)

3 t - 5

What is the derivative of x/(10-(10)/x) ?
The derivative of x/(10-(10)/x) is 1/10+(10)/(x^2)
What is the first derivative of x/(10-(10)/x) ?
The first derivative of x/(10-(10)/x) is 1/10+(10)/(x^2)