What is the derivative of 2x^3-5x+4 ?

The derivative of 2x^3-5x+4 is 6x^2-5

What is the first derivative of 2x^3-5x+4 ?

The first derivative of 2x^3-5x+4 is 6x^2-5

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\frac{d}{d x} (2 x^{3} - 5 x + 4)

6 x^{2} - 5

Solution steps

\frac{d}{d x} (2 x^{3} - 5 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (4) = 0

= 6 x^{2} - 5 + 0

Simplify

= 6 x^{2} - 5

\frac{2 x ^{2} + 1}{x}

\frac{d}{d x} (\frac{25 - x ^{2}}{32 x})

\int_{0}^{2} f (x) d x

\int_{- 1}^{1} x^{2} e^{x^{3} + 1} d x

What is the derivative of 2x^3-5x+4 ?
The derivative of 2x^3-5x+4 is 6x^2-5
What is the first derivative of 2x^3-5x+4 ?
The first derivative of 2x^3-5x+4 is 6x^2-5