What is the derivative of-6sin(2x+3cos(3x)) ?

The derivative of-6sin(2x+3cos(3x)) is -12cos(2x)-9sin(3x)

What is the first derivative of-6sin(2x+3cos(3x)) ?

The first derivative of-6sin(2x+3cos(3x)) is -12cos(2x)-9sin(3x)

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\frac{d}{d x} (- 6 sin (2 x) + 3 cos (3 x))

- 12 cos (2 x) - 9 sin (3 x)

Solution steps

\frac{d}{d x} (- 6 sin (2 x) + 3 cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (6 sin (2 x)) + \frac{d}{d x} (3 cos (3 x))

\frac{d}{d x} (6 sin (2 x)) = 12 cos (2 x)

\frac{d}{d x} (3 cos (3 x)) = - 9 sin (3 x)

= - 12 cos (2 x) - 9 sin (3 x)

\frac{d}{d x} (x (55 - 0.5 x) - 110)

\frac{d}{d t} (e^{3 i t})

\int \frac{x ^{3}}{x ^{2} - 100} d x

n = 1 \sum \infty \frac{2}{n ^{2} + 4 n + 2}

\frac{d}{d x} (\frac{sin ( 5 x )}{cos ( 6 x )})

What is the derivative of-6sin(2x+3cos(3x)) ?
The derivative of-6sin(2x+3cos(3x)) is -12cos(2x)-9sin(3x)
What is the first derivative of-6sin(2x+3cos(3x)) ?
The first derivative of-6sin(2x+3cos(3x)) is -12cos(2x)-9sin(3x)